1-(1⼀2+1⼀4+1⼀8+1⼀16+1⼀32+1⼀64+1⼀128)=?

2024-12-25 14:12:47
推荐回答(2个)
回答1:

1-(1/2+1/4+1/8+1/16+1/32+1/64+1/128)
=1-[1/2+(1/2-1/4)+(1/4-1/8)+(1/8-1/16)+(1/16-1/32)+(1/32-1/64)+(1/64-1/128)]
=1-(1/2+1/2-1/128)
=1-(1-1/128)
=1-1+1/128
=1/128

回答2: