求解答一道高一物理题(波义尔定律)

2025-03-23 19:02:20
推荐回答(1个)
回答1:

2.P0=76cmHg v0=44s
P1=P0+Lsin30^0=88cmHg
p1v1=p0v0 L1=38cm
(2)p2=P0-Lsin30^0=64cmHg
p2v2=p0v0 L2=52.25cm
(3)p3=P0+L=100cmHg
p3v3=p0v0 L3=33.44cm
3.p1=p0-19=57cmHg v1=40s
p2=p0=76cmHg
p1v1=p2v2 v2=30s
加入水银H
H=10+10+19=39cm