51问答网 > 溶质质量分数为20%的硝酸钠溶液100g，欲将其溶质质量分数增大一倍，可采用的方法是（　　）A．加入100g40

溶质质量分数为20%的硝酸钠溶液100g，欲将其溶质质量分数增大一倍，可采用的方法是（　　）A．加入100g40

2025-03-16 12:53:24
推荐回答（1个）
回答1：

A、加入100g40%的硝酸钠溶液时，溶液中溶质的质量分数为：
100g×20%+100g×40%
200g
×100%＝30%，故选项采用的方法错误；
B、设需要蒸发水的质量为x，（100g-x）×40%=100g×20%，x=50g，应蒸发掉50g水，故选项采用的方法错误．
C、设需要再溶解该物质的质量为y，（100g+y）×40%=100g×20%+y，y=33.3g，故选项采用的方法错误．
D、如果蒸发掉50g的水，则溶液中溶质的质量分数为：═
20g
100g?50g
×100%＝40%，故选项采用的方法正确．
故选D．

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