设等差数列{a n }的前n项和为S n ,已知a 3 =5,S 3 =9.(Ⅰ)求首项a 1 和公差d的值;(Ⅱ)若S n =100

2025-03-06 23:13:42
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回答1:

(Ⅰ)∵等差数列{a n }中,a 3 =5,S 3 =9,
a 1 +2d=5
3 a 1 +
3×2
2
d=9

解得a 1 =1,d=2,
(Ⅱ)∵a 1 =1,d=2,
S n =n+
n(n-1)
2
×2
=n 2 =100,
∴n=10.