计算:2005×(1⼀1×2+1⼀2×3+1⼀3×4+…+1⼀2003×2004+1⼀2004×2005)

2025-02-25 13:29:00
推荐回答(2个)
回答1:

2005×(1/1×2+1/2×3+1/3×4+…+1/2003×2004+1/2004×2005)
=2005×[(1-1/2)+(1/2-1/3)+(1/3-1/4)+......+(1/2004-1/2005)]
=2005×(1-1/2005)
=2005-1
=2004

回答2:

2005×(1/1×2+1/2×3+1/3×4+…+1/2003×2004+1/2004×2005)
=2005×(1-1/2+1/2-1/3+1/3-1/4+…+1/2003-1/2004+1/2004-1/2005)
=2005×(1-1/2005)
=2005×2004/2005
=2004