解:1/x-1+3/2-x-x的平方=1/(x-1)+3/(2-x-x^2)=(x+2)/(x+2)(x-1)-3/(x+2)(x-1)=(x+2-3)/(x+2)(x-1)=(x-1)/(x+2)(x-1)=1/(x+2)当x=-5/2,原式=1/(-5/2+2)=1/(-1/2)=-2
