C15混凝土中的砂子、碎石、水泥送检批次计算

2025-03-15 15:28:48
推荐回答(4个)
回答1:

水泥:543*310=168330/1000=168.33T (水泥送检一次)
砂子:543*645=350235/堆积密度=方数 (砂子400立方米送检一次,不足一次按一次算,如果算出来小于400方送一次,大于400方小于800方送检2次,大于800方小于1200方送检3次,依次类推)

碎石:543*1225=665175/堆积密度=方数 (按砂子的计算方法)

手工码字,采纳请好评,谢谢

回答2:

1、水泥、沙子各一次,石子2次,砼试块6组,建议做不少于10组。
2、C15的混凝土配合比:水泥330 砂子619 河石1315 水160 (27.5水泥)
水泥280 砂子750 石1250 水170。
3、混凝土的强度等级是指混凝土的抗压强度。混凝土的强度等级应以混凝土立方体抗压强度标准值划分。采用符号C与立方体抗压强度标准值(以N/mm^2; 或 MPa计)表示。

回答3:

砂石400方或者600吨一次,水泥散装500吨,袋装200吨一次,不足时按一次送检。

回答4:

水泥、沙子各一次,石子2次,砼试块6组,建议做不少于10组。

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