∫sin3xsin5xdx怎么算

2025-02-28 01:07:55
推荐回答(1个)
回答1:

∫sin3xsin5xdx
=-(1/2)∫(cos8x-cos2x)dx
=-(1/2)((1/8)sin8x-(1/2)sin2x)+C
=(-1/16)sin8x+(1/4)sin2x+C