(x²+xy+y²)/(x+y)=[(x+y)²-xy]/(x+y)x=-2-根号3y=-2+根号3x+y=-4 xy=1所以原式=(16-1)/-4=-3.75
(x²+xy+y²)/(x+y)=(x²+2xy+y²-xy)/(x+y)=[(x+y)²-xy]/(x+y)=(x+y)-xy/(x+y)x+y=-2根号3xy=-1代入得-(11/6)根号3
-(11/6)根号3