有一道高难四年级应用题!高分悬赏快来答!

2024-12-18 18:58:04
推荐回答(4个)
回答1:

第一次相遇AB两车共行了1个全程,A车行了1个75千米

第二次相遇AB两车共行了3个全程,A车行了3个75千米,

也就是75×3=225千米,同时也是1个全程多55千米

所以,甲乙两地的距离是

75×3-55=170(千米)

够详细了吧!

回答2:

因为第一次在离A地75千米处相遇,说明A一次行75千米。第二次相遇时共走了3个全程,所以A走了75*3=225千米,再减去55千米就是一个全程。

75*3-55
=225-55
=170(千米)
答:AB相距170千米。

回答3:

75×3 的意义就是两车共同走完全程一次,甲车行75千米,相遇二次,共走了3个全程。

-55的意义就是甲车与乙车相遇二次后,走了三个全程,甲车走了一个全程多55千米。减去55米不就是全程吗。

回答4:

假设甲从A地出发:第一次相遇时,两车共行驶了一个AB距离,甲车就行驶了75千米,那么甲乙两车第二次想遇时他们就已经行驶了3个AB间的距离,那么甲车也就行驶了一个AB距离加55千米,也就是是75*3.所以75*3-55=AB距离=170千米

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