1) x+m/x=c+m/cx-c+m(1/x-1/c)=0(x-c)+m(c-x)/(xc)=0(x-c)[1-m/(cx)]=0得x-c=0, 或1-m/(cx)=0得x=c, 或x=m/c 2)方程化为：x-1+2/(x-1)=(a-1)+2/(a-1)因此得：x-1=a-1, 或x-1=2/(a-1)得：x=a, 或x=1+2/(a-1)
