一道求极限的高数题

请问这道题怎么做?答案是1⼀12
2024-12-31 01:07:30
推荐回答(2个)
回答1:

如图

回答2:

原式 = lime^(2-2cosx){e^[x^2-(2-2cosx)] - 1} / x^4
= lim{e^[x^2-(2-2cosx)] - 1} / x^4
= lim[x^2-(2-2cosx)]/x^4 = lim(2x-2sinx)/(4x^3)
= lim(x-sinx)/(2x^3) = lim(1-cosx)/(6x^2)
= lim(x^2/2)/(6x^2) = 1/12