客车上午八点从甲地开往乙地,每小时行90km,半小时后货车从乙地出发开往甲地,每小时行60km。甲

2025-03-14 21:43:53
推荐回答(3个)
回答1:

(645-90x0.5)÷(90+60)
=600÷150
=4小时

4+0.5=4.5小时

所以 12点半相遇

请好评

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回答2:

方法一:
甲用的的时间,比乙多半小时,即1/2 h
∴设乙用了x h,则甲用了(x+1/2)h

则90(x+1/2)+60x=645
解出x=4

即乙8:30出发,4小时候两车相遇
所以,是在12:30时两车相遇。

方法二:
设甲用了x h,乙用了y h
所以,
90x+60y=645
x-y=1/2
解得,
x=9/2
y=4

所以,乙用了4h,因为乙比甲迟半小时,即8:30出发,
所以12:30时,两车相遇。

回答3:

设相遇的时候乙走了x小时,甲则0.5+x
60x+90(0.5+x)=654
150x=609
x=4.06小时
甲是4.56小时
时间8:00+4.56小时=12:36:36
12点36分俯筏碘禾鄢鼓碉态冬卡36秒在中相遇

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