数奥难题

2024-12-12 16:36:53
推荐回答(2个)
回答1:

(1)老师对学生说:我像你这么大时,你才4岁,等到你长到我这么大时,我就52岁了。问:老师学生各多少岁?

因为你是小学的奥数,所以就不用方程了。
做类似的题目有个小技巧,就是二人的年龄差就是:[52-4]/3=16岁

那么学生的年龄是:4+16=20岁,老师的年龄是:20+16=36岁

(2)设1、3、9、27、81、243是6个给定的数,从这6个数中每次取1个,或取几个不同的数(每个数只能取一次)求和,可以得到一个新数,这样共得63个新数,如果把它按从小到大的顺序依次排列起来是1、3、4、9、10、12......那么第60个数是多少?

因为这里的最大数是243,且远远大于81,所以第60个数肯定是243与另外一个数的和。倒推一下,第63个数是243+81

第62个是:243+27,第61个是:243+9
那么第60个是:243+3=246

(3)时钟在8点至9点之间,时针、分针在什么时候形成一条直线?

一分钟分针走6度,时针走0。5度,8点到9点之间,二针成一线时,分针在时针后:180度。
设X分时二针成一线。所以有:
6X+180=0。5X+8*30

X=120/11

答:在8点120/11分时二针成一线。

回答2:

1解:(52-4)/3=16(岁)
所以老师:4+16+16=36(岁)
学生:4+16=20(岁)
2解:第63个数是243+81=324,第62个数是243+27=270,
第61个数243+9=252,第60个数243+4=247
3解:

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