用LED显示多路DS18b20采集的温度(51C语言)

2024-12-28 02:50:34
推荐回答(1个)
回答1:

这是一路的
#include
#define uchar unsigned char
#define uint unsigned int
sbit DS=P2^2; //define interface
uint temp; // variable of temperature
uchar flag1; // sign of the result positive or negative
sbit dula=P2^6;
sbit wela=P2^7;
unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,
0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
unsigned char code table1[]={0xbf,0x86,0xdb,0xcf,0xe6,0xed,0xfd,
0x87,0xff,0xef};

void delay(uint count) //delay
{
uint i;
while(count)
{
i=200;
while(i>0)
i--;
count--;
}
}
void dsreset(void) //send reset and initialization command
{
uint i;
DS=0;
i=103;
while(i>0)i--;
DS=1;
i=4;
while(i>0)i--;
}

bit tmpreadbit(void) //read a bit
{
uint i;
bit dat;
DS=0;i++; //i++ for delay
DS=1;i++;i++;
dat=DS;
i=8;while(i>0)i--;
return (dat);
}

uchar tmpread(void) //read a byte date
{
uchar i,j,dat;
dat=0;
for(i=1;i<=8;i++)
{
j=tmpreadbit();
dat=(j<<7)|(dat>>1); //读出的数据最低位在最前面,这样刚好一个字节在DAT里
}
return(dat);
}

void tmpwritebyte(uchar dat) //write a byte to ds18b20
{
uint i;
uchar j;
bit testb;
for(j=1;j<=8;j++)
{
testb=dat&0x01;
dat=dat>>1;
if(testb) //write 1
{
DS=0;
i++;i++;
DS=1;
i=8;while(i>0)i--;
}
else
{
DS=0; //write 0
i=8;while(i>0)i--;
DS=1;
i++;i++;
}

}
}

void tmpchange(void) //DS18B20 begin change
{
dsreset();
delay(1);
tmpwritebyte(0xcc); // address all drivers on bus
tmpwritebyte(0x44); // initiates a single temperature conversion
}

uint tmp() //get the temperature
{
float tt;
uchar a,b;
dsreset();
delay(1);
tmpwritebyte(0xcc);
tmpwritebyte(0xbe);
a=tmpread();
b=tmpread();
temp=b;
temp<<=8; //two byte compose a int variable
temp=temp|a;
tt=temp*0.0625;
temp=tt*10+0.5;
return temp;
}

void readrom() //read the serial
{
uchar sn1,sn2;
dsreset();
delay(1);
tmpwritebyte(0x33);
sn1=tmpread();
sn2=tmpread();
}

void delay10ms() //delay
{
uchar a,b;
for(a=10;a>0;a--)
for(b=60;b>0;b--);
}

void display(uint temp) //显示程序
{
uchar A1,A2,A2t,A3;
A1=temp/100;
A2t=temp%100;
A2=A2t/10;
A3=A2t%10;
dula=0;
P0=table[A1]; //显示百位
dula=1;
dula=0;

wela=0;
P0=0x7e;
wela=1;
wela=0;
delay(1);

dula=0;
P0=table1[A2]; //显示十位
dula=1;
dula=0;

wela=0;
P0=0x7d;
wela=1;
wela=0;
delay(1);

P0=table[A3]; //显示个位
dula=1;
dula=0;

P0=0x7b;
wela=1;
wela=0;
delay(1);
}

void main()
{
uchar a;
do
{
tmpchange();
for(a=10;a>0;a--)
{ display(tmp());
}
} while(1);
}