简单计算一下即可，答案如图所示
I = ∫arcsin√xdx/√(1-x)令 u = arcsin√x， 则 sinu = √x， x = (sinu)^2, I = ∫u 2sinucosudu/cosu = 2∫usinudu= -2∫udcosu = -2ucosu + 2∫cosudu= -2ucosu + 2sinu + C = -2√(1-x) arcsin√x + 2√x + C
