1.X(2-√2)=(√2-2) X(2-√2)=(√2-2) X(2-√2)=-1(2-√2) x=1 2.(√5+√2)-(√5-√2) =(√5+√2+√5-√2)(√5+√2-√5+√2) =2√5*2√2 =4√10 3.√8+3√(1/3)-1/(√2)+(√3)/2 =2√2+3*(√3)/3-(√2)/2+(√3)/2 =2√2+√3-(√2)/2+(√3)/2 =(3/2)√3+(3/2)√2 4.(√3+√2+√5)(√3-√2-√5) =(√3+√2+√5)[√3-(√2+√5)] =(√3)-(√2+√5) =3-(2+5+2√10) =3-7-2√10 =-4-2√10 5.√8-2√32+√50 =5*3√2-2*4√2+5√2 =√2(15-8+5) =12√2 6.√6-√3/2-√2/3 =√6-√6/2-√6/3 =√6/6 7. (√45+√27)-(√4/3+√125) =(3√5+3√3)-(2√3/3+5√5) =-2√5+7√5/3 8.(√4a-√50b)-2(√b/2+√9a) =(2√a-5√2b)-2(√2b/2+3√a) =-4√a-6√2b 9.(√32-3√3)(4√2+√27) =(4√2-3√3)(4√2+3√3) =(4√2)^2-(3√3)^2 =32-27 =5 10.1+√2-√3)(1-√2+√3) =[1+(√2-√3)][1-(√2-√3)] =1-(√2-√3)^2 =1-(2+3+2√6) =-4-2√6 拼你十道。。求采纳。 追问: 一元二次方程 可否在给几道 回答: 1)x^2+4x+3-15=0 x^2+4x-12=0 (x-2)(x+6)=0 则x=2或 -6 (2) (2x-1)(x+3)=0 则x=1/2 或 -3 (3) (x-√2)^2=0 则x=√2 (4) 1/2(x^2+2x+1)+1/8-1/2=0 1/2(x+1)^2=3/8 (x+1)^2=3/4 则x=√3/2 -1 或 -√3/2 -1 (5) 3(x-2)^2+x(x-2)=0 (x-2)[3(x-2)+x]=0 (x-2)(4x-6)=0 则x=2 或 3/2 补充: 求采纳啊。