0.1g氯化钠溶于水配成250ml溶液,此溶液的质量浓度是多少？解：浓度%=溶质g / (溶质g+溶剂g）浓度%= 0.1 / (0.1+25) =0.1/25.1=0.3984%约等于：0.4%.
:0.1/(250+0.1)*100%=0.03998%此溶液的浓度是0.03998%
