已知x^2-3x+1=0,求x^3⼀(x^6+1)和x^5+(1⼀x^5)的值

如题,急求啊~~~
2024-12-22 13:57:57
推荐回答(1个)
回答1:

由 x²-3x+1=0 ,可得:
x+1/x = 3 ,
x²+1/x² = (x+1/x)²-2 = 7 ,
x³+1/x³ = (x+1/x)(x²+1/x²)-(x+1/x) = 18 ,
所以,
x^3/(x^6+1) = 1/(x³+1/x³) = 1/18 ;
x^5+1/x^5 = (x²+1/x²)(x³+1/x³)-(x+1/x) = 123 。