若f(x)=(1⼀x)^2+1⼀x-2为y=x^2+x-2和哪个函数的复合函数?

2025-03-22 06:05:32
推荐回答(1个)
回答1:

z=f(y)=1/y, y=f(x)=x^2 (or x^2+2x-2) ==> z=f(x)=1/x^2 (or 1/( x^2+2x-2))