求值域,详细过程

2025-02-23 12:35:31
推荐回答(1个)
回答1:

y=(4x+3)/(x²+1)
yx²+y=4x+3
yx² - 4x + y-3 = 0
△ = 4²-4y(y-3)≥0
y(y-3)-4≤0
y²-3y-4≤0
(y+1)(y-4)≤0
-1≤y≤4