(2014?莆田模拟)在探究凸透镜成像规律的实验中,凸透镜的焦距为15cm.(1)如图所示,将蜡烛、凸透镜、

2025-03-14 21:56:12
推荐回答(1个)
回答1:

(1)实验过程中,调整凸透镜和光屏的高度,使蜡烛、凸透镜和光屏三者中心大致在同一高度,目的是使烛焰的像成在光屏的中央.
用调整好后的装置进行实验,发现无论怎么移动光屏,都无法再光屏上找到像,其原因可能是:①烛焰到凸透镜的距离不大于一倍焦距,此时成放大的正立的虚像或不成像,即光屏是不能承接的;
②烛焰到凸透镜的距离略大于一倍焦距,此时成放大的倒立的实像,像距非常大,由于光具座的长度有限,所以光屏也无法承接清晰的像;
③凸透镜的焦距太大,此时物距可能一直在一倍焦距以内,此时成放大的正立的虚像,即光屏是不能承接的.
(2)凸透镜的焦距为15cm,当烛焰距凸透镜35cm时,u>2f,成倒立、缩小的实像,若蜡烛向远离凸透镜的方向移动,物距增大,像距变小,屏幕上的像将变小,日常生活中利用这一原理制成的光学仪器是照相机.
故答案为:(1)同一高度;蜡烛在焦点上(或蜡烛在焦点以内等);(2)缩小;变小;照相机.

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