二极管反接电源,是为了防止反接吗?

2025-03-15 04:02:38
推荐回答(4个)
回答1:

不是防反接,应该还是保护作用,Vcc5和Vcc3.3供应的都是功能强大的CPU之类的IC等低压大电流负载,价值比较高昂。而这两组电压一般来自开关电源的12V输出电压,经三端稳压器或DC-DC变换得到。如果因为某种异常,导致内部调整管击穿,进而导致输出的电压高到输入电压,如Vcc5达到12V,Vcc3.3达到5V或者12V,都会将IC置于危险之中。接上这些稳压二极管之后,如发生上述失效,将会直接导致稳压管击穿,开关电源就会因负载短路而停止工作。

回答2:

这两个都是稳压二极管,在电路中起过压保护作用。当稳压二极管负极上所接的电源电压超出稳压管稳压值时,稳压管呈现大电流反向导通状态,其两端电压稳定在稳压值(根据保护线路的不同设计,可能稳压,也可能直接将前级保险管熔断)。如果线路前端设计有保险管,电流超出保险管的电流值将熔断,以保护电路后级器件。
至于稳压管的稳压电压值需查找专门的晶体管手册。

回答3:

二极管的单向导电性,电源接反了直接导通IN5822,保护后级电路,其实这里1N5822主要起过压吸收作用,异常电压或高谐波超过IN5822击穿电压时,in5822导通,保护D3以免击穿.

回答4:

这个是稳压管吧?你查看一下稳压管的工作原理。

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