2√3tan15°+tan15°= (2√3+1)tan15°= (2√3+1)tan(60°-45°)= (2√3+1)(tan60°-tan45°)/(1+tan60°tan45°)= (2√3+1)(√3-1)/(1+√3)= (2√3+1)(√3-1)²/[(1+√3)(√3-1)] = (2√3+1)(4-2√3)/2= (2√3+1)(2-√3)= 4√3+2-2×3-√3= 3√3 - 4