△ABC中,角A,B,C所对的边分别是a,b,c,且cosA= 4 5 .(1)求 sin 2 B+C 2

2025-03-09 08:04:56
推荐回答(1个)
回答1:

(1) sin 2
B+C
2
+cos2A
= cos 2
A
2
+cos2A

=
1+cosA
2
+2 cos 2 A-1

=
1+
4
5
2
+2×
16
25
-1
=
59
50
(6分)
(2)∵ cosA=
4
5
sinA=
3
5
  S=
1
2
bcsinA
=
1
2
×2c×
3
5
=3 
∴c=5,a 2 =b 2 +c 2 -2bccosA= 4+25-2×2×5×
4
5
=13
 
a=
13
(7分)