做个锥形漏斗,请高人教我画下扇形图,谢谢

2024-12-17 10:56:49
推荐回答(2个)
回答1:

圆锥形漏斗的母线长为: (900^2+((614-57)/2)^2)^0.5=942.1cm
扇形大圆半径为: 942.1*(614/2)/((614-57)/2)=1038.5cm
扇形小圆半径为: 1038.5-942.1=96.4cm
扇形的圆心角为: PI*614/1038.5=1.857弧度=1.857*180/PI=106.4度

回答2:

制作一个上口直径d1=381.5CM,下口直径d2=50CM.坡高为h=150cm的圆锥形漏斗怎样画扇形图?
扇形的大圆弧半径为R1,小圆弧半径为R2,弧所对的圆心角为A。
R1-R2=(h^2+((d1-d2)/2)^2)^0.5
=(150^2+((381.5-50)/2)^2)^0.5
=223.5466
A=PI*d1/R1=PI*d2/R2
d1/R1=d2/R2
R2=(d2/d1)*R1=(50/381.5)*R1
R1-R2=R1-(50/381.5)*R1=223.5466
381.5*R1-50*R1=223.5466*381.5=85283.01094
331.5*R1=85283.01094
R1=257.26CM
R2=(50/381.5)*R1=(50/381.5)*257.26=33.72CM
A=PI*d1/R1
=PI*381.5/257.26
=4.658707弧度
=4.658707*180/PI
=266.92度