(x-1⼀2)(x+1⼀2)(x^2-1⼀2x+1⼀4)(x^2+1⼀2x+1⼀4)

计算这一题
2024-12-23 01:23:00
推荐回答(2个)
回答1:

(x-1/2)(x+1/2)(x^2-1/2x+1/4)(x^2+1/2x+1/4)
=[(x-1/2)(x^2+1/2x+1/4)][(x+1/2)(x^2-1/2x+1/4)]
=(x^3-1/8)(x^3+1/8)
=x^6-1/64

回答2:

(x-1/2)(x+1/2)(x-1/2)^2(x+1/2)^2
=(x-1/2)^3(x+1/2)^3