[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]⼀4y,其中x=1⼀2,y=1⼀3

2024-12-29 10:40:40
推荐回答(2个)
回答1:

[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y
=(4x^2+4xy+y^2+y^2-4x^2-8xy+2y^2)/4y
=(-4xy+4y^2)/4y
=-x+y
=-1/2+1/3
=-1/6

回答2:

先化简得:3/4-x/y
再代入,得-3/4