求下列极限,大一新生才学,麻烦过程详细一些,感谢了?!

2025-03-12 13:22:54
推荐回答(2个)
回答1:


回答2:

let
y=x-1
lim(x->1) (1-x^2)/sin(πx)
=lim(y->0) (1-(1+y)^2)/sin(π(1+y))
=lim(y->0) (-2y-y^2 )/sin(πy)
=lim(y->0) (-2y-y^2 )/(πy)
=lim(y->0) (-2-y )/π
=-2/π