51问答网 > 一台100kvA变压器、三相四线供电、线路为150平方裸铝线、长度2500米、问电压降多少、能否正

一台100kvA变压器、三相四线供电、线路为150平方裸铝线、长度2500米、问电压降多少、能否正

2025-03-16 18:08:04
推荐回答（3个）
回答1：

　　I=P/√3 U线=100*1000/1.732*400=100000/692.8=144.3A 理论COSφ=0.8 P=80kw
ρ=铝0.0315Ω.㎜2/m（铰）S=150mm2（铝） l=2500m
R=ρL/S=0.0315*2500/150=78.75/150=0.53Ω
用欧姆定律估算：△U=I R=144.3*0.53=76.48V
估算结果负荷80kw时末端电压损失76.48v，结论不能用。

回答2：

铝线电阻，欧=0.0283×2500/150=0.472欧。
100kvA电流180A。
压降=电阻×电流=0.472×180=84.96V
满戴时压降偏大，半戴时勉强可用。

回答3：

你还没说实际用电负荷多大？

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