求解一元二次不等式:-x2+2x+3>0

求解一元二次不等式:-x2+2x+3>0-x2即:-x的平方
2025-01-07 00:48:56
推荐回答(4个)
回答1:

即x^2 - 2 * x - 3 < 0
(x - 3) * (x + 1) < 0
则 -1 < x < 3

回答2:

-x2+2x+3>0
x2-2x-3<0
(x-3)(x+1)<0
-1

回答3:

-(x²-2x-3)>0
-(x-3)(x+1)>0
(x-3)(x+1)<0
-1

回答4:

-x²+2x+3>0
x²-2x-3=(x-3)(x+1)<0
-1