请采纳
根据题意，x²+2xy+y²-2y²=0(x+y)²-2y²=0(x+y+√2y)(x+y-√2y)=0x=-(1+√2)y或x=-(1-√2)yy/x=-1/(1+√2)或-1/(1-√2)y/x=-√2+1或y/x=√2+1
如图
