三年级奥数:三位数的各位数字之和等于10,这样的三位数共有多少个? 不能用代数。

答案是45的请不要作答。
2025-03-25 14:18:25
推荐回答(3个)
回答1:

答案是54个。三位数即百位十位个位,要使三个数位上的和为10,而保证数要有意义,百位上的数不能为零,即百位上的数为1.......9,而另两个数位的和为9......1,然后再接着确定十位,最后根据前两位去确定个位:(我就举百位为1的让你参考),主要的要掌握解决的方法,以后再出此类型的题就不会再被难倒了)。
百十个
1 0 9
1 1 8
1 2 7
1 3 6
1 4 5
1 5 4
1 6 3
1 7 2
1 8 1
1 9 0

回答2:

百位上是“1”的数有109、118、127、136、145、154、163、172、181、190共10个,
百位上是“2”的数有208、217、226、235、244、253、262、271、280共9个,
百位上是“3”的数有307、316、325、334、343、352、361、370共8个,
……
……
……
百位上是“9”的数有901、910共2个,
所以共有10+9+8+7+……+2=1/2(10+2)(10-2+1)=54个数。
*楼上掉了一个数550

回答3:

109
190
118
181
127
172
136
163
145
154
208
280
217
271
226
262
235
253
244
307
370
316
361
325
352
334
343
406
460
415
451
424
442
433
505
514
541
523
532
604
640
613
631
622
703
730
712
721
802
820
811
901
910

最傻的方法,53个

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