求一道应用题的解法!急急急急急!!!!

2024-12-19 16:03:35
推荐回答(6个)
回答1:

设乙厂次品数为a,则甲厂产品中的正品数量为3a
甲厂次品数量为b,则乙厂正品的数量为4b
由于甲乙两厂生产产品的数量相等
所以3a+b=4b+a
化简得a=1.5b
甲乙两厂生产的正品数量之比3a:4b
把a=1.5b代入,就是4.5b:4b=9:8

回答2:

正 次
甲 3x y

乙 4y x

列这么一个表,再设x,y
令3x+y=4y+x
得x:y=3:2
所以答案是3x:4y=9:8

回答3:

应该是四比三

回答4:

设甲厂生产的正品数量为X,乙厂生产的次品数量为Y,则由题意得以下等式:
X=3Y
4(1-X)=1-Y
解得
x=9/11
y=3/11
所以想X/(1-Y)=9:8

回答5:

设甲厂产品中的次品数量为x件,乙厂产品中的次品数量为y件,由“甲厂产品中的正品数量是乙厂次品数的3倍,乙厂正品的数量是甲厂次品数量的4倍”可知甲厂产品中的正品数量为3y件,乙厂产品中正品数量为4x件,再根据“甲乙两厂生产产品的数量相等”列出方程x+3y=y+4x 移项得2y=3x 即y=1.5x 则甲厂产品中的正品数量为3y=3*1.5x=4.5x件,那么,甲乙两厂生产的正品数量之比是4.5x:4x=9:8
回答完毕
谢谢楼主 请给分

回答6:

4:3

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