求解几道数学题123456789qwertyuiopasdfghjklzxcvbnm

2024-12-28 09:14:41
推荐回答(3个)
回答1:

1.151807041=12321^2
2.9^(x+1)-9^x=72
9^x(9-1)=72
9^x=9
x=1
3.???
4.设快车速度x,慢车速度y
168+184=4(x+y)
16x=16y+168+184
所以x=55 y=33
5.(1)甲每天各需费用x元,乙每天各需费用y元
x+y=3520/8
6x+12y=3480
所以x=300,y=140
(2)甲单独完成此工程需a天,乙单独完成此工程需b天
8/a+8/b=1
6/a+12/b=1
所以a=12,b=24
(3)甲单独完成此工程需要费用=12*300=3600
乙单独完成此工程需费用24*140=3360<甲单独完成此工程需要费用

回答2:

第一题
不会

2.若9^x+1-3^2x=72 求x的值?
9^(x+1)-9^x=72
9^x(9-1)=72
9^x=9
x=1

3.某同学做一道代数题:求。。。
不会

4.一列快车长168米,一列慢车长184米,如果两车相向而行,从相遇到离开需4秒,如果同向而行,从快车追击慢车道离开需16秒,求两车速度?
设快车速度x,慢车速度y
168+184=4(x+y)
16x=16y+168+184

所以x=55 y=33

5.一工程,甲乙两人合作8天可完成任务。需用飞3520元,若甲独做6天后剩下的工程,尤乙独做,还需12天才能完成,这样的费用需3480元,问(1)甲乙两人单独完成此工程每天各需费用多少元?(2)甲乙两人单独完成此工程各需多少天?(3)哪个人单独完成此工程费用较省?
(1)甲每天各需费用x元,乙每天各需费用y元
x+y=3520/8
6x+12y=3480
所以x=300
y=140
(2)甲单独完成此工程需a天,乙单独完成此工程需b天
8/a+8/b=1
6/a+12/b=1
所以a=12 b=24
(3)甲单独完成此工程需要费用=12*300=3600
乙单独完成此工程需费用24*140=3360<甲单独完成此工程需要费用

回答3:

第1题
用计算器按按吧.应该不是脑筋急转弯吧.

第2题
9^x(9-1)=72
9^x=9
x=1

第3题
真的只有1项吗?

第4题
(168+184)/4=88
(168+184)/16=22
快车的速度=50 慢车的速度=38

第5题
(1)设:甲,乙每天费用需Q,P.
8(Q+P)=3520
6Q+12P=3480
Q=300
P=140
(2)设:甲,乙每天工作量为X,Y.总工作量为1
8(X+Y)=1
6X+12Y=1
X=1/12
Y=1/24
1/X=12
1/Y=24
(3)
Q/X=3600
P/Y=3360

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