推荐回答(6个)
1
解:设:x辆车
45x+15(学生人数)=60x-60(学生人数)
15x=75
x=5
60*5-60=240(人)
答:5辆车 240个学生
(15+60)/(60-45)
=75/15
=5(辆)
5*45+15=240(人)
(我记得这叫和差问题? 不记得了貌似是的)
230/45=46/9(5又5/1)
300/60=5
(以上皆为平均每人费用)
答:60坐合算
吾可是自己算的-v-
1.首先解:设租用了X辆45座客车。
45X+15=60(X-1)
45X+15=60X-60
60+15=15X
X=5
车算出来了,再是5*45+15=240(人),这个学校有240人
2.45*4+60*1=240(人) 4*230+300*1=1220(元)
要最合算,就要刚刚好坐满,题目说:“若租用若干辆45座客车,则有15人没有座位”,那么45座客车1辆+没座位的15人,刚好可以坐60人,就只需要1辆60座客车,剩下的刚刚好坐满4辆45座客车。
打了半天,希望采纳 谢谢啦
(*^__^*) 嘻嘻……
1.首先解:设租用了X辆45座客车。
45X+15=60(X-1)
45X+15=60X-60
60+15=15X
X=5
车算出来了,再是5*45+15=240(人),这个学校有240人
2.45*4+60*1=240(人) 4*230+300*1=1220(元)
要最合算,就要刚刚好坐满,题目说:“若租用若干辆45座客车,则有15人没有座位”,那么45座客车1辆+没座位的15人,刚好可以坐60人,就只需要1辆60座客车,剩下的刚刚好坐满4辆45座客车。
打了半天,希望采纳
(1) (15+60)÷(60-45)=5(辆)
60×(5-1)=240(人)
答:240人。
(2) 230×(5+1)=1380(元)
300×(5-1)=1800(元)
1380<1800
答:租45座的合适。
我觉得我的第二题跟大家都不一样,不知我的理解是误区,还是大家,不过自认我的比较好。
解:(1)首先根据车变而总人数未变的情况列出等式
n 为45座客车需要的数量 则有
45n+15=60(n-1) 解方程得 n=5
所以总人数是45n+15=240
答:这个学校六年级学生240人
(2)采用分类考虑
假如只用6辆45座车 则需啊租金 1380
5辆45座车 60座补足 则需要租金 1450
4辆45座车 则需要租金 1220
3辆45座车 则需要租金 1290
2辆45座车 则需要租金 1360
1辆45座车 则需要租金 1430
0辆45座车 则需要租金 1200
从以上情况分析最合算的是 4辆60座客车
答:租4辆60座客车最经济合算,因为租金最低。
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解:设租了x辆车。
租用若干辆45座客车,则有15人没有座位
所以有45x+15人
若租用同样数量的60座客车,则一辆车为空车
所以有60(x-1)人
所以45x+15=60(x-1)
45x+15=60x-60
15x=75
x=5
45x+15=240
答: 这个学校一共有学生240人。
若租45座需要:(5+1)×220=1320(元)
租60座需要:300×(5-1)=1200(元)
因为1200<1320,
所以应租60座客车。
答:应租60座客车。
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